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9x^2+27x-360=0
a = 9; b = 27; c = -360;
Δ = b2-4ac
Δ = 272-4·9·(-360)
Δ = 13689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13689}=117$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-117}{2*9}=\frac{-144}{18} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+117}{2*9}=\frac{90}{18} =5 $
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